Checkerboard - Intro to Java ProgrammingYouTube↗  IA↗(long shot)
Education  3.1K views 9 likes 7 dislikes   23 Feb 2015
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This problem could get pretty complicated, so let's write some test cases out.
Este problema se podría complicar bastante, así que escribamos algunos casos de prueba.
I'll index spots by row and column. So 2, 2 would be right here, and that spot
Pondré índices para puntos por fila y columna. Así que 2, 2 estaría bien aquí, y ese punto
should be blue. So, we need an expression that when given 2 and 2 gets 0. The
debe ser azul. Por lo tanto, necesitamos una expresión que cuando de 2 y 2 obtenga cero. El
spot 3, 3 should also be blue. So again, we need a zero. 2, 3 should be red.
punto 3, 3 también debe ser azul. Así que de nuevo, necesitamos un cero. 2, 3 debe ser rojo.
So, that should be a 1. And 3, 2 should be red. So, also 1. So, what's an
Así que ese debe ser un 1. Y 3, 2 debe ser rojo. Así que también 1. Así que, ¿cual es una
expression I could try to use to turn 2 and 2 into 0, 3 and 3 into 0, 2 and 3
expresión que podría tratar de utilizar para convertir 2 y 2 a 0, 3 y 3 a 0, 2 y 3
into 1, and 3 and 2 into 1. It kind of looks like maybe I'm taking the mod of
en 1, y 3 y 2 en 1? Parece que tal vez estoy tomando el mod de
these and adding that together. So, row mod 2 plus column mod 2. Let's see what
estos y añadiendolos juntos. Así que, fila mod 2 mas columna mod 2. Veamos que
this gives in each case. 2 mod 2 would be 0. 0 and 0 gives 0, so that's good. 3
nos da en cada caso. 2 mod 2 sería 0. 0 y 0 da 0, así que está bien. 3
mod 2 is 1 and 2 mod 2 is 0, so that gives 1. The same will happen here. This
mod 2 es 1 y 2 mod 2 es 0, por lo que da 1. Lo mismo ocurrirá aquí. Este
one doesn't quite work. 3 mod 2 is 1 and 3 mod 2 is also 1, so I would get 2.
no funciona muy bien. 3 mod 2 es 1 y 3 mod 2 es también 1,así que podría obtener 2.
But then maybe if I just mod the whole thing by 2 again, then I would get 0
Pero entonces tal vez si solo uso mod para todo por 2 otra vez, entonces obtendría 0
which is the same. The 2 would turn into 0 and the ones would stay. So, this
que es lo mismo. El 2 se convertiría en 0 y los unos se quedarían. Así que esta
expression might work. Let's test it out in BlueJ. First, I'll check my test
expresión podría funcionar. Vamos a probarla en BlueJ. Primero voy a verificar mi prueba
and put some actual values in it. The test cases I came up with were 2, 2; 3,
y a poner algunos valores reales en ella. Los casos de prueba que se me ocurrieron fueron 2,2, 3,3,
3; 2, 3 and 3, 2. For 2, 2 I expected 0, and I expected the same thing for 3,
2, 3 y 3, 2. Para 2, 2 0 me esperaba 0, y me espera lo mismo para
3. At 2, 3 I expected 1, so 1, and at 3, 2 I also expected 1. So, my tester
3,3. En 2, 3 esperaba 1, así que 1, y en 3, 2 también esperaba 1. Así que mi probador
should be good to go. Now, I'll try putting that expression into the actual
debe estar listo. Ahora voy a tratar de poner esa expresión en el programa
program. In the checker board painter, instead of returning five, I want to
real. En el CheckerBoardPainter, en lugar de devolver cinco, quiero
return row mod 2, plus col mod 2, and then all mod 2. I don't have to put these
devolver fila mod 2, más columna mod 2 y después todo mod 2. No tengo que poner estos
in parentheses because the plus has lower precedence. And let's try it. If I
entre paréntesis porque el más tiene precedencia menor. Y vamos a intentarlo. Si
run the tester, my actual and expected values match up. But could we make this
ejecuto el probador, mis valores reales y esperados coinciden. ¿Pero podríamos hacer esto
any simpler? What if I noticed that adding an even number plus an even number
más simple? ¿Qué pasa si me di cuenta de que añadir un número par más un número par
gives me another even number. And an odd number plus an odd number gives me
me da otro número par? Y un número impar más un número impar me da
another even number, but odd plus even or even plus odd both give odd numbers.
otro número par, pero el impar más par o par mas impar, ambos dan números impares.
Then I can just add row and column, and take the mod 2 right at the end.
Entonces puedo solo agregar la fila y la columna y tomar el mod 2 justo al final.
Because if they match, their sum is even. And if they don't match, the sum is
Porque si coinciden, su suma es par. Y si ellos no coinciden, la suma es
odd. So, I'll just get rid of the mod 2 and the mod 2. If I change it in the
impar. Así que sólo voy a deshacerme del mod 2 y el mod 2. Si lo cambio en el
checkerboard painter, erase that and erase that. What will my test say? Is this
CheckerBoardPainter, borro eso y borro eso. ¿Qué dirá mi prueba? ¿Esto sigue siendo
still the same? And if I run the test again, still works. As a bonus question,
lo mismo? Y si ejecuto la prueba otra vez, aún funciona. Como pregunta adicional,
what if instead of returning 0 when they match and 1 when they don't match, I
¿Qué pasaría si en lugar de devolver 0 cuando coinciden y 1 cuando no coinciden,
wanted to return one when they match and zero when they don't match. How would
quisiera devolver 1 cuando coincidan y 0 cuando no coincidían? ¿Cómo harías
you do that? I won't go over it, but it's something to think about.
eso? No voy a abordar esto, pero es algo en lo que tienes que pensar.
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